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In Fig., if AB || CD, then the value of x isA. 20°B. 30°C. 45°D. 60° |
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Answer» Given that, AB ‖ CD and transversal cuts them Let, ∠1 = 120° + x and ∠2 = x ∠1 = ∠3 (Alternate angles) ∠3 = 120° + x (i) ∠2 + ∠3 = 180°(Linear pair) x + 120° + x = 180° 2x = 60° x = 30° |
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