1.

In Fig. if ∠ACB = 40°, ∠DPB = 120°, find ∠CBD.

Answer»

We have, 

∠ACB = 40° 

∠DPB = 120° 

∠ADB = ∠ACB = 40° 

(Angle on same segment) 

In triangle PDB, 

By angle sum property 

∠PDB + ∠PBD + ∠BPD = 180° 

40° + ∠PBD + 120° = 180° 

∠PBD = 20° 

Therefore, 

∠CBD = 20°



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