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In Fig. if ∠ACB = 40°, ∠DPB = 120°, find ∠CBD. |
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Answer» We have, ∠ACB = 40° ∠DPB = 120° ∠ADB = ∠ACB = 40° (Angle on same segment) In triangle PDB, By angle sum property ∠PDB + ∠PBD + ∠BPD = 180° 40° + ∠PBD + 120° = 180° ∠PBD = 20° Therefore, ∠CBD = 20° |
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