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In Fig.if ∠BAC = 60° and ∠BCA = 20°, find ∠ADC. |
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Answer» By using angle sum property in triangle ABC, ∠B = 180° – (60° + 20°) = 100° In cyclic quadrilateral ABCD, we have ∠B + ∠D = 180° ∠D = 180° – 100° = 100° |
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