1.

In Fig., if CP || DQ, then the measure of x isA. 130°B. 105°C. 175°D. 125°

Answer»

Given that,

CP ‖ BQ

Produce CP to E

So,

PE ‖ BQ and AB cuts them

∠QBE = ∠CBA = 105°(Corresponding angles)

In ΔECA

∠CEA + ∠ECA + ∠EAC = 180°

105° + ∠ECA + 25° = 180°

∠ECA = 50°

∠PCA + ∠ECA = 180°(Linear pair)

x + 50° = 180°

x = 130°



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