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1. |
In Fig. if O is the circumcentre of Δ ABC, then find the value of ∠OBC + ∠BAC. |
Answer» ∠OBC + ∠CBA = ∠OBA ∠OBC + 30° = 50° ∠OBC = 20° ∠OBC + ∠BAC = ∠OBC + ∠CAB = 20° + 110° = 130° |
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