1.

In Fig. if O is the circumcentre of Δ ABC, then find the value of ∠OBC + ∠BAC.

Answer»

∠OBC + ∠CBA = ∠OBA 

∠OBC + 30° = 50° 

∠OBC = 20° 

∠OBC + ∠BAC = ∠OBC + ∠CAB 

= 20° + 110° 

= 130°



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