1.

In fig, it is given that AE= AD and BD=CE. Prove that∆AEB~∆ADC

Answer»

In ΔAEB and ΔADC AE = AD (Given) ∠EAB =∠DAC (common) AB = AC { :- AE = AD and EC = BD }

thus

Δ AEB ≈ΔADC (SAS congurency)



Discussion

No Comment Found