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In fig, it is given that AE= AD and BD=CE. Prove that∆AEB~∆ADC |
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Answer» In ΔAEB and ΔADC AE = AD (Given) ∠EAB =∠DAC (common) AB = AC { :- AE = AD and EC = BD } thus Δ AEB ≈ΔADC (SAS congurency) |
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