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In Fig.O is the centre of the circle. Find ∠CBD. |
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Answer» Given that, ∠BOC = 100° By degree measure theorem, ∠AOC = 2 ∠APC 100° = 2∠APC ∠APC = 50° Therefore, ∠APC + ∠ABC = 180° (Opposite angles of a cyclic quadrilateral) 50° + ∠ABC = 180° ∠ABC = 130° Therefore, ∠ABC + ∠CBD = 180° (Linear pair) 130° + ∠CBD = 180° ∠CBD = 50° |
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