1.

In Fig.O is the centre of the circle. Find ∠CBD.

Answer»

Given that, 

∠BOC = 100° 

By degree measure theorem, 

∠AOC = 2 ∠APC 100° = 2∠APC 

∠APC = 50° 

Therefore, 

∠APC + ∠ABC = 180° 

(Opposite angles of a cyclic quadrilateral) 

50° + ∠ABC = 180° 

∠ABC = 130° 

Therefore, 

∠ABC + ∠CBD = 180° 

(Linear pair) 

130° + ∠CBD = 180° 

∠CBD = 50°



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