In Fig. P and Q are centres of two circles intersecting at B and C. AC

1.	In Fig. P and Q are centres of two circles intersecting at B and C. ACD is a straight line. Then, ∠BQD =
Answer» We know that, ∠ACB = \(\frac{∠APB }{2}\) ∠ACB = \(\frac{150 }{2}\) ∠ACB = 75° Since, ACD is a straight line, so ∠ACB + ∠BCD = 180° 75° + ∠BCD = 180° ∠BCD = 180° – 75° = 105° Now, ∠BCD = \(\frac{1}{2}\)Reflex ∠BQD 105° = (360° - ∠BQD) 210o = 360° - ∠BQD ∠BQD = 360° – 210° Therefore, ∠BQD = 150°

In Fig. P and Q are centres of two circles intersecting at B and C. ACD is a straight line. Then, ∠BQD =

Answer»

We know that,

∠ACB = \(\frac{∠APB }{2}\)

∠ACB = \(\frac{150 }{2}\)

∠ACB = 75°

Since,

ACD is a straight line, so

∠ACB + ∠BCD = 180°

75° + ∠BCD = 180°

∠BCD = 180° – 75°

= 105°

Now,

∠BCD = \(\frac{1}{2}\)Reflex ∠BQD

105° = (360° - ∠BQD)

210o = 360° - ∠BQD

∠BQD = 360° – 210°

Therefore,

∠BQD = 150°

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In Fig. P and Q are centres of two circles intersecting at B and C. ACD is a straight line. Then, ∠BQD =

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