In Fig., PQ || RS. If ∠1=(2a+b)° and ∠6=(3a–b)°, then the meas

1.	In Fig., PQ \|\| RS. If ∠1=(2a+b)° and ∠6=(3a–b)°, then the measure of ∠2 in terms of b is (a) (2+b)° (b) (3–b)° (c) (108–b)° (d) (180–b)°
Answer» (c) (108–b)^o From the question it is given that, ∠1 = (2a + b)^o and ∠6 = (3a – b)^o Since ∠5 and ∠6 these two forms a linear pair Then, ∠5 = (180-3a + b)^o … [equation 1] ∠5 = ∠1 = (180-3a + b)^o [Because Corresponding angles] …equation (2) On equating equation (1) and equation (2) we get, 2a + b = 180-3a + b 5a = 180 a = 36⁰ Since ∠1 and ∠2 forms a linear pair so ∠2 = 180⁰– 2a-b

In Fig., PQ || RS. If ∠1=(2a+b)° and ∠6=(3a–b)°, then the measure of ∠2 in terms of b is (a) (2+b)° (b) (3–b)° (c) (108–b)° (d) (180–b)°

Answer»

(c) (108–b)^o

From the question it is given that, ∠1 = (2a + b)^o and ∠6 = (3a – b)^o

Since ∠5 and ∠6 these two forms a linear pair

Then,

∠5 = (180-3a + b)^o … [equation 1]

∠5 = ∠1 = (180-3a + b)^o [Because Corresponding angles] …equation (2)

On equating equation (1) and equation (2) we get,

2a + b = 180-3a + b

5a = 180

a = 36⁰

Since ∠1 and ∠2 forms a linear pair so

∠2 = 180⁰– 2a-b