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In Fig., ∠PQR = 100°. where P, Q and R are points on a circle with centre O. Find ∠OPR. |
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Answer» If ∠PQR = 100°, then ∠OPR = ? ∠PQR = 100°. ∴ ∠POR = ? ∠POR = 2 × ∠PQR = 2 × 100° ∠POR = 200° ∴ ∠POR – Reflex angle ∠POR = 360° ∴ ∠POR = 360 – 200 ∴ ∠POR = 160° In ∆POR, OP = OR radii. ∴ ∠OPR = ∠ORB ∴ ∠OPR + ∠ORP + ∠POR = 180° ∠OPR + ∠OPR + 160 = 180 2∠OPR+ 160 = 180 2∠OPR = 180 – 160 2∠OPR = 20 ∠OPR = \(\frac{20}{2}\) ∴ ∠OPR= 10°. |
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