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In Fig. two congruent circles with centres O and O’ intersect at A and B. If ∠AO’B = 50°, then find ∠APB. |
Answer» ∠AO'B = 50° Since, both the triangle are congruent so their corresponding angles are equal. ∠AOB = AO'B = 50° Now, ∠APB = \(\frac{AOB}{2}\) ∠APB = \(\frac{50}{2}\) = 25° |
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