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In figure, AB and CD are diameters of a circle with centre O. If ∠OBD = 50°, find ∠AOC. |
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Answer» Given: ∠OBD = 50° Here, AB and CD are the diameters of the circles with centre O. ∠DBC = 90° ….(i) [Angle in the semi-circle] Also, ∠DBC = 50° + ∠OBC 90° = 50° + ∠OBC or ∠OBC = 40° Again, By degree measure theorem: ∠AOC = 2 ∠ABC ∠AOC = 2∠OBC = 2 x 40° = 80° |
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