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In figure, AB II PQ II CD,AB x units, CD -y units andPQ z units. Prove that +3 |
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Answer» See the diagram. ΔABD andΔPQD are similar, as the corresponding sides are parallel. x/z = BD / QD => 1/x = QD /(z * BD) ΔCDB andΔPQB are similar, as corresponding sides are parallel. y/z = BD/ BQ => 1/y = BQ / (z * BD) Add the two equations: 1/x + 1/y = (BQ + QD) / (z * BD) = 1 /zPlease like the solution 👍 ✔️👍 |
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