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In figure, ABE is a in which `AE=BE` . Circle passing through A and B intersects AE and BE at D and C respectively. Prove that `DC||AB`. |
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Answer» We are given, `AE = BE`, `:. /_EAB = /_EBA->(1)` Also, we know, exterior angle of a cyclic quadrilateral is equal to opposite interior angle. `:. /_EBA = /_EDC->(2)` From (1) and (2), `/_EAB = /_EDC` As both these angles are equal, it implies `DC` and `AB` are parallel to each other. |
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