In figure, AOB is a straight line. Find the value of x. Hence, find

1.	In figure, AOB is a straight line. Find the value of x. Hence, find
Answer» AOB is a straight line\xa0{tex}\\therefore{/tex}\xa0{tex}\\angle{/tex}AOC + {tex}\\angle{/tex}COD +\xa0{tex}\\angle{/tex}DOB = 180°{tex}\\Rightarrow{/tex}\xa0(3x – 5)° + 55° + (x + 20)° = 180°{tex}\\Rightarrow{/tex}\xa03x – 5° + 55° + x + 20° = 180° {tex}\\Rightarrow{/tex}\xa04x + 70° = 180°\xa0{tex}\\Rightarrow{/tex}\xa04x = 180° – 70°{tex}\\Rightarrow{/tex}\xa04x = 110° {tex}\\Rightarrow{/tex}\xa0x =110/4 = 27 ½°Therefore, {tex}\\angle{/tex}AOC = 3x – 5° = 3 {tex}\\times{/tex}\xa027½° – 5 = 77½°and {tex}\\angle{/tex}BOD = x + 20 = 27 ½ + 20 = 47\xa0½\u200b\u200b\u200b\u200b\u200b\u200bo

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