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In figure , assuming the diodes to be ideal , A. `D_(1)` is forward biased and `D_(2)` is reverse biased and hence current flows from A to BB. `D_(2)` is forward biased and `D_(1)` is reverse biased and hence no current flows from B to A and vice-versa.C. `D_(1) " and " D_(2)` are both forward biased and hence current flows from A to BD. `D_(1) " and " D_(2)` are both reverse biased and hence no current flows from A to B and vice-verse. |
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Answer» Correct Answer - B In the given circuit `p-`side of `p - n` function `D_(1)` is connected to lower voltage and `n-`side of `D_(1)` to higher voltage. Thus D is reverse blased. The `p-`side of `p -n` junction `D_(2)` is at higher potential and `n-`side of `D_(2)` is at lower potential. Therefore `D_(2)` is forward blassed Hence, current flows through the junction B to A |
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