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In figure ,`BA _|_ AC,DE _|_DF `such that BA =DE and BF=EC.Show that `Delta ABC cong Delta DEF.` |
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Answer» Given In figure ,`BA _|_ AC,DE _|_DF `such that BA =DE and BF=EC. To show `" "Delta ABC cong Delta DEF. ` `Proof Since " " BF=EC ` On adding CF both sides we get `" "BF+CF=EC+CF` `In Delta ABC and Delta DEF, " "angleA=angleD=90^(@) " "[because BA_|_ AC and DE _|_ DF]` `" "BC=EF" "["from Eq.(i)"]` `and " " BA =DE " "["given"]` `therefore " "Delta ABC cong Delta DEF " "["by RHS congruence rule"]` |
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