In figure BD and CE intersect each other at the point P. Is`DeltaPBC~D – InterviewSolution

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1.	In figure BD and CE intersect each other at the point P. Is`DeltaPBC~DeltaPDE`? Why?
Answer» True In `DeltaPBC and DeltaPDE`, `angleBPC=angleEPD` [vertically opposite angle] Now `(PB)/(PD)=5/10=1/2` and `(PC)/(PE)=(6)/(12)=1/2` From Eqs. (i) and (ii) `(PB)/(PD)=(PC)/(PE)` Since. One angle of `DeltaPBC` is equal to one angle of `DeltaPDE` and the sides including these angles are proportional, so both triangles are similar. Hence. `DeltaPBC~DeltaPDE`, by SAS similarity criterion.

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