1.

In figure, DEFG is a square and ∠BAC=90o, Prove that (i)△AGF∼△DBG (ii)△AGF∼△EFC (iii)△DBG∼△EFC (iv)DE2=BD×EC

Answer»

In figure, DEFG is a square and BAC=90o, Prove that
(i)AGFDBG
(ii)AGFEFC
(iii)DBGEFC
(iv)DE2=BD×EC



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