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In figure, if `angleDAB=60^(@),angleABD=50^(@),"then "angleACB ` is equal to A. `60^(@)`B. `50^(@)`C. `70^(@)`D. `80^(@)` |
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Answer» Correct Answer - C Given, `angleDAB=60^(@),angleABD=50^(@)` Since, `angleADB=angleACB` [angles in same segment of a circle are equal] In `DeltaABD,angleABD+angleADB+angleDAB=180^(@)` [by angle sum property of a triangle] `:. 50^(@)+angleADB+60^(@)=180^(@)` `rArr angleADB=180^(@)-110^(@)=70^(@)` Form Eq. (i), `angleACB=angleADB=70^(@)` |
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