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In figure if TP and TQ are the two tangents to a circle with centre O so that ∠POQ = 110°, then find the value of ∠PTQ. |
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Answer» PT amd QT are tangents to the circle with centre O. ∴ OP ⊥ PT and OQ ⊥ QT i.e., ∠POQ = 110°, ∠OPT = 90° ∠OQT = 90° In quad OPTQ we have, ∠POQ + ∠OPT + OQT + ∠PTQ = 360° ∠PTQ = 360° – (110° + 90° + 90°) ∠PTQ = 360° – 290° ∠PTQ = 70° |
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