1.

In figure, O is the centre of the circle. Find ∠CBD.

Answer»

Given: ∠BOC = 100° 

By degree measure theorem: ∠AOC = 2 ∠APC 

100° = 2 ∠APC 

or ∠APC = 50° 

Again, ∠APC + ∠ABC = 180° (Opposite angles of a cyclic quadrilateral) 

50° + ∠ABC = 180° 

or ∠ABC = 130° 

Now, ∠ABC + ∠CBD = 180° (Linear pair) 

130° + ∠CBD = 180° 

or ∠CBD = 50°



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