In figure, PQ = PR, show that PS > PQ – InterviewSolution

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1.	In figure, PQ = PR, show that PS > PQ
Answer» In ∆PQR ∴ PQ = PR ⇒ ∠PRQ = ∠PQR ....(i) [Angles opposite to equal sides] In ∆PSQ, SQ is produced to R ∴ Ext. ∠PQR > ∠PSQ ....(ii) ∠PRQ > ∠PSQ [By eq. (i) and (ii)] ⇒ ∠PRS > ∠PSR ⇒ PS > PR [Sides opposite to greater angles is larger] But, PR = PQ ∴ PS > PQ

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