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In figure , the plates of a parallel plate capacitors have unequal charges. Its capacitance is C. P is a point outside the capacitor and close to the plate of charge -Q. The distance between the plates is d. Then A. a point charge at point P will experience electric force due to the capacitorsB. the potential difference between the plates will be `3Q//2C`.C. the energy stored in the electric field in the region between the plates is `9Q^2//8C`.D. the force on one plate due to the other plate is `Q^2//2piepsilon_0d^2`. |
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Answer» Correct Answer - A::B::C a.,b.,c. i. `E=(2Q)/(2Aepsilon_(0))+(Q)/(2Aepsilon_(0))=(3Q)/(2Aepsilon_(0))` or `E=(3)/(2)(Q)/(cd)` or `Ed=(3Q)/(2C)=V` ii. `F=E(-Q)=((2Q)/(2Aepsilon_(0)))xx((-Q))/(1)=(Q^(2))/(Aepsilon_(0))` `=(Q^(2))/(Aepsilon_(0))` ltbgt iii. Energy `=(1)/(2)epsilon_(0)E^(2)Ad=(1)/(2)epsilon_(0)((3Q)/(2Cd))^(2)Ad=(9)/(8)(Q^(2))/(C)` |
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