1.

In figure, two circles intersect at A and B. The centre of the smaller circle is O and it lies on the circumference of the larger circle. If ∠APB = 70°, find ∠ACB.

Answer»

By degree measure theorem: ∠AOB = 2 ∠APB 

so, ∠AOB = 2 × 70° = 140° 

Since AOBC is a cyclic quadrilateral, we have 

∠ACB + ∠AOB = 180°

∠ACB + 140° = 180° 

∠ACB = 40°



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