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In figures `triangle ABC and triangleDEF` ar similar , the areas of `triangle ABC` is 9 sq. m and that of `triangleDEF` is 16 sq. cm. if EF= 4.2 cm, find BC. |
Answer» ar`(triangleABC)= 9 sq.cm` `ar triangle(DEF) = 16 sq.c m` EF=4.2 cm BC= ? Since the ratio of areas of two similar triangles is equal to ratio of square on their corresponding sides ` ( ar(triangleABC))/(ar(triangleDEF))= (BC^(2))/(EF^(2))` `Rightarrow 9/16 = ((BC)/(EF))^(2)` `(BC)/(4.2)= 3/4` `Rightarrow BC= (3xx 4.2)/4= 3.15 cm ` |
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