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In G.P 6th term is -1/32 & 9th term is 1/256 then 11th term………… |
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Answer» Sixth term = T6 = -1/32 ninth term = T9 = 1/256 then , common ratio = R = ? 11th term = T11 = ? R9-6 = (1/256)/-1/32 R3 = 1/256 × -32 R3 = 1/-8 R3 = -1/8 R3 = (-1/2)3 R = -1/2 . T6 = a(R)n-1 -1/32 = aR6-1 -1/32 = aR5 -1/32 = a × (-1/2)5 -1/32 = a × -1/32 (-1/32)/(-1/32) = a -1/32 × -32 = a -1×-1 = a 1 = a a = 1 T11 = aRn-1 T11 = (1)(-1/2)11-1 T11 = (-1/2)10 T11 = 1/1024 |
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