In given figure, STAPRORQPS-3 cm and SR = 4 cm. Find the ratio of the

1.	In given figure, STAPRORQPS-3 cm and SR = 4 cm. Find the ratio of the area of ÎPST to the area of.T,
Answer» Given:ST \|\| RQPS= 3 cmSR = 4cm We know that the ratio of areas of two similar triangles is equal to the ratio of squares of their corresponding sides. ar(∆PST) /ar(∆PRQ)= (PS)²/(PR)² ar(∆PST) /ar(∆PRQ)= 3²/(PS+SR)² ar(∆PST) /ar(∆PRQ)= 9/(3+4)²= 9/7²=9/49 Hence, the required ratio ar(∆PST) :ar(∆PRQ)= 9:49

In given figure, STAPRORQPS-3 cm and SR = 4 cm. Find the ratio of the area of ÎPST to the area of.T,

Answer»

Given:ST || RQPS= 3 cmSR = 4cm

We know that the ratio of areas of two similar triangles is equal to the ratio of squares of their corresponding sides.

ar(∆PST) /ar(∆PRQ)= (PS)²/(PR)²

ar(∆PST) /ar(∆PRQ)= 3²/(PS+SR)²

ar(∆PST) /ar(∆PRQ)= 9/(3+4)²= 9/7²=9/49

Hence, the required ratio ar(∆PST) :ar(∆PRQ)= 9:49