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In Haber process 30 litre of dihydrogen and 30 litres of dinitrogen were taken for reaction which yielded only`50%` of the expected product. What will be the composition of gaseous mixture under the aforesaid condition in the end ?A. 20 L ammonia , 10 L nitrogen , 30 L hydrogenB. 20 L ammonia , 25 L nitrogen , 15 L hydrogenC. 20 L ammonia , 20 L nitrogen , 20 L hydrogenD. 10 L ammonia , 25 L nitrogen , 15 L hydrogen |
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Answer» Correct Answer - D `underset(10 L)underset(1 V)(N_(2))+underset(30L)underset(3V)(3H_(2))tounderset(20 L)underset(2V)(2NH_(3))` As only `50%` of the expected product is formed, hence only 10 L of `NH_(3)` is formed. Thus , for the production of 10 L of `NH_(3)` , 5 L of `N_(2) and 15 L` of `H_(2)` are used and composition of gaseous mixture under the aforesaid condition in the end is `H_(2)=30-15=15 L` `N_(2)=30-5 =25 L` `NH_(3)=10 L` |
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