In Haber's process 50.0 g of N_(2)(g) and 10.0 g of H_(2)(g) are mixed to produce NH_(3)(g). What is the number of moles of NH_(3)(g) formed?

In Haber's process 50.0 g of N_(2)(g) and 10.0 g of H_(2)(g) are mixed

1.	In Haber's process 50.0 g of N_(2)(g) and 10.0 g of H_(2)(g) are mixed to produce NH_(3)(g). What is the number of moles of NH_(3)(g) formed?
Answer» 3.33 2.36 2.01 5.36 Answer :A