In hot alkaline solution, Br_2disproportionates to 3Br_(2)- 6OH^(-) rarr 5Br^(-) + BrO_3^(-) +3H_(2)O .The equivalent weight of Br_(2)is 3M/x (mol wt = M). Then X is?

In hot alkaline solution, Br_2disproportionates to 3Br_(2)- 6OH^(-) ra

1.	In hot alkaline solution, Br_2disproportionates to 3Br_(2)- 6OH^(-) rarr 5Br^(-) + BrO_3^(-) +3H_(2)O .The equivalent weight of Br_(2)is 3M/x (mol wt = M). Then X is?
Answer» <BR> Solution :For `3Br_(2)`MOLECULES change in. no = 5 Change in OXIDATION number for 1 MOLECULE = `5/3` =n-factor equivalent weight of `Br_(2)= M/(5//3) =(3M)/5`