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In how many ways 4 women draw water from 4 taps, if no tap remains unused? |
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Answer» 1st woman can draw water from anyone of the 4 taps. Now, as, it is given, that, No tap should remain unused So, 2nd woman can draw water from any of the remaining 3 taps. Similarly, 3rd women can draw water from any of the remaining 2 taps. And, 4th woman have to draw water from the remaining 1 tap. As, The operations are dependent, So, Total number of ways = 4\(\times\)3\(\times\)2\(\times\)1 = 4! Alternative Approach : The number of permutations of 4 objects taken 4 at a time is = 4P4 = 4!. |
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