1.

In how many ways 5 boys and 3 girls can be seated in a row so that no two girls are together?

Answer»

5 boys can be seated among themselves in 5P5 = 5! Ways. After this arrangement, we have to arrange the three girls in such a way that in between two girls there atleast one boy. So the possible places girls can be placed with the x symbol given below. 

x B x B x B x B x B x 

∴ There are 6 places to seated by 3 girls which can be done 6P3 ways. 

∴ Total number of ways = 5! x 6P3 

= 120 x (6 x 5 x 4) 

= 120 x 120 

= 14400



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