1.

In how many ways 5 red, 4 blue and 1 green balls can be arranged in a rowd) 10

Answer»

Total no. of Arrangements = 10 ! / 5! x 4! x 1!

= 10*9*8*7*6*5*4*3*2/5*4*3*2*4*3*2*1

= 10*3*7

= 210 ways



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