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In how many ways 5 red, 4 blue and 1 green balls can be arranged in a rowd) 10 |
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Answer» Total no. of Arrangements = 10 ! / 5! x 4! x 1! = 10*9*8*7*6*5*4*3*2/5*4*3*2*4*3*2*1 = 10*3*7 = 210 ways |
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