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In How Many Ways A Team Of 11 Must Be Selected From 5 Men And 11 Women Such That The Team Must Comprise Of Not More Than 3 Men? |
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Answer» The team may consist of 0 MEN + 11 women, 1 men + 10 women, 2 men + 9 women, or 3 men + 8 women. So Number of WAYS are = 11C11+5C1×11C10+5C2×11C9+5C3×11C8 = 2256. The team may consist of 0 men + 11 women, 1 men + 10 women, 2 men + 9 women, or 3 men + 8 women. So Number of ways are = 11C11+5C1×11C10+5C2×11C9+5C3×11C8 = 2256. |
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