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In how many ways ANUBHAW can be arranged in which all consonants are together?1. 2882. 8283. 2664. 622 |
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Answer» Correct Answer - Option 1 : 288 Concept used: Number of all the permutations of n things = n! Calculation: The given word is ANUBHAW in this word we take all consonants as one letter AUANBHW in this word NBHW treat as one letter This arrangement has 4 letters of which A appears two times ⇒ Number of ways = 4!/2! ⇒ (4 × 3 × 2!)/2! ⇒ 12 Now, four consonants can be arranged among them as 4! = 4 × 3 × 2× 1 ⇒ 24 ways Required number of ways = 12 × 24 ⇒ 288 ∴ The required number of ways is 288 |
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