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In how many ways can 5 girls and 3 boys be seated in a row so that no two boys are together? |
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Answer» First, we seat the 5 girls in 5! ways. For each such a arrangement, the three boys can be seated only at the ‘6’ cross marks places x G x G x G x G x G x Three boys can be selected in 6P3 ways Hence total number of ways = 5 x 6P3 = (5 x 4 x 3 x 2 x 1) x (6 x 5 x 4) = 14400 |
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