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In how many ways can the letters of the word ‘ARRANGE’ be arranged such that the two r’s do not occur together? |
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Answer» There are two a’s, two r’s in the word ‘arrange’, therefore the number of arrangements = \(\frac{7!}{2!2!}=1260.\) ...(1) The number of arrangements in which the two r’s occur together = \(\frac{6!}{2!}\) = 360 ...(2) ∴ The number of arrangements in which two r’s do not occur together = (1) – (2) = 1260 – 360 = 900. |
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