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In how many ways the number 10800 can be resolved as a product of two factors? |
Answer» Let `N=10800=2^(4)xx3^(3)xx5^(2)` Here, N is not a perfect square [`because` power of 3 is odd] Hence, the number of ways=`(1)/(2)(4+1)(3+1)(2+1)=3`. |
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