1.

In hydrogen atom the kinetic energy of electron is 3.4 eV. The distance of that electron from the nucleus

Answer»

`2.11 A^@`
`0.529 A^@`
`1.587A^@`
`21.16A^@`

SOLUTION :3.4 eV is KE .` e^-` in `2^(nd)` ORBIT
`THEREFORE r = 4(0.529) A^@ = 2.116 A^@`


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