In hydrogen spectrum L_(alpha) line arises due to transition of electron from the orbit n=3 to the orbit n=2. In the spectrum of singly ionized helium there is a line having the same wavelength as that of the L_(alpha) line. This is due to the transition of electron from the orbit:

In hydrogen spectrum L_(alpha) line arises due to transition of electr

1.	In hydrogen spectrum L_(alpha) line arises due to transition of electron from the orbit n=3 to the orbit n=2. In the spectrum of singly ionized helium there is a line having the same wavelength as that of the L_(alpha) line. This is due to the transition of electron from the orbit:
Answer» `N = 3 to n=2` `n = 2 to n = 1` `n = 5 to n = 3` `n = 6 to n = 4` Solution :`""H_(alpha) ""He^+` `(1)^2 xx R(1/(2^2) - 1/(3^2)) = (2^2) xx R (1/(n_1^2 - 1/(n_2^2)))` On SOLVING ,`n_1 = 4 and n_2 = 6`