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In hydrozen atom, the electron is making `6.6xx10^(15)` revolution per second in a circular path of radius `0.53A^@`. What is the magnetic induction produced at the centre of the orbit? |
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Answer» Here, `v=6.6xx10^(15)rps`, `r=0.53xx10^(-10)m`, Current due to orbital motion of electron is: `I=e/T=ev=(1.6xx10^(-19))xx(6.6xx10^(15))=1.056xx10^-3A` `B=(mu_0)/(4pi)(2pinI)/(r)=(10^-7xx2xx(22//7)xx1xx(1.056xx10^-3))/((0.53xx10^(-10)))=12.5 Wb//m^2` |
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