in ine gou13. Ten men, working for 6 days of 10 hourseach,521finish of

1.	in ine gou13. Ten men, working for 6 days of 10 hourseach,521finish of a piece of work. How many menworking at the same rate and for the samenumber of hours each day, will be required tocomplete the remaining work in 8 days?
Answer» Ans :- 1 day working of 10 men = (5/21)×(1/6) 1 day working of 1 man =(5/21) ×(1/6)×(1/10) 8 day working of 1 men =(5/21)×(1/6)×(1/10)×8 = 2/63 remaining work = 1-(5/21) = 16/21 hence, number of men required to complete the work in 8 days = (16/21)÷(2/63) =(16×63)/(2×21) = 8×3 = 24 men

in ine gou13. Ten men, working for 6 days of 10 hourseach,521finish of a piece of work. How many menworking at the same rate and for the samenumber of hours each day, will be required tocomplete the remaining work in 8 days?

Answer»

Ans :- 1 day working of 10 men = (5/21)×(1/6)

1 day working of 1 man =(5/21) ×(1/6)×(1/10)

8 day working of 1 men =(5/21)×(1/6)×(1/10)×8 = 2/63

remaining work = 1-(5/21) = 16/21

hence, number of men required to complete the work in 8 days = (16/21)÷(2/63)

=(16×63)/(2×21) = 8×3 = 24 men