1.

In inequality log 1/2(x​​​​​​2​​​​​-6x+12) ≥ -2 there is one step which says (x-2)(x-4) ≤ 0,. then how can we conclude that x<2 and x>4 ?

Answer»

In inequality log 1/2(x​​​​​​2​​​​​-6x+12) ≥ -2 there is one step which says (x-2)(x-4) ≤ 0,. then how can we conclude that x<2 and x>4 ?



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