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In inequality log 1/2(x2-6x+12) ≥ -2 there is one step which says (x-2)(x-4) ≤ 0,. then how can we conclude that x<2 and x>4 ? |
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Answer» In inequality log 1/2(x2-6x+12) ≥ -2 there is one step which says (x-2)(x-4) ≤ 0,. then how can we conclude that x<2 and x>4 ? |
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