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In `K_4[Fe(CN)_6]` the EAN of Fe isA. (a) `33`B. (b) `35`C. (c) `36`D. (d) `26` |
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Answer» Correct Answer - C EAN=Atomic number-Oxidation state + 2 x number of Ligands `=26-2+2(6)=36`. |
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