1.

In long form of periodic table, an elem ent has electronic configurationIs^(2) 2s^(22)p^(6)3s^(2)3p^(3) Thus what will be the atomic no. of elem ent ? Which is just below this elem ent in its group ?

Answer»

23
16
47
33

Solution :The GIVEN CONFIGURATION indicates Z = 15, and outerm ost configuration `3s^(2) 3p^(3)` ..... indicates group `15^(th) , row 3^(rd)therefore`Next row `4^(th)` and group `15^(th)` element will behaving Z = (15 + 18) = 33


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