1.

In modern periodic table, if an element has electronic configuration 1s^(2), 2s^(2), 2p^(6), 3s^(2), 3p^(4), then what will be the atomic number of element, which is just below the element in its group ?

Answer»

18
34
45
24

Solution :34
Electronic configuration of the element
`1S^(2) 2s^(2) 2p^(6) 3s^(2) 3P^(4)`
` :. ` TOTAL electrons in it = 16 and Z = 16
Which INDICATES element is S(Z = 16) of`III^(rd)` Period, and`16^(th)` /VIB GROUP. Element just below S in same group is Se having atomic number 34.


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