In mutarotation of alpha-D Glucose hArr beta-D Glucose equilibrium constant is 1.8. At equilibrium what will be the percentage of alpha-D Glucose ?

In mutarotation of alpha-D Glucose hArr beta-D Glucose equilibrium con

1.	In mutarotation of alpha-D Glucose hArr beta-D Glucose equilibrium constant is 1.8. At equilibrium what will be the percentage of alpha-D Glucose ?
Answer» 35.8 64.3 55.6 44.4 Solution :`{:(,alpha-"D-GLUCOSE" hArr, BETA-"D-Glucose"),("INITIAL",1,0),("At EQUILIBRIUM" , 1-alpha,alpha):}` `K=alpha/(1-alpha)`=1.8 `alpha=1.8-1.8alpha` `therefore 2.8 alpha-1.8` `therefore alpha`=0.642 `therefore 1-alpha`=0.358 So, at the equilibrium of `alpha`-D Glucose =35.8%