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In nuclear fission, 0.01% mass is converted into energy. The energy released by the fission of 100 kg mass will be:A. `9 xx 10^(15) j`B. `9 xx 10^(11) kJ`C. `9 xx 10^(17) j`D. `9 xx 10^(13) J` |
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Answer» Correct Answer - b `Delta m = 100 xx (0.01)/(100) = 0.01 kg` `E = Delta mc^(2) = 0.01 xx (3 xx 10^(8))^(2) J` `= 9 xx 10^(14) J = 9 xx 10^(11) kJ` |
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