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In one experiment, certain amount of NH_(4)I(s) was heated rapidly in a closed container at 375^(@)C. The following equilibrium was established: NH_(4)I(s)hArrNH_(3)(g)+HI(g) Excess of NH_(4)I(s) remained unreacted in the flask and equilibrium pressure was 304mm of Hg. After some time, the pressure started increasing further owing to the dissociation of HI. 2HI(g)hArrH_(2)(g)+l_(2)(g) K_(C)=0.010 calculate final pressure. |
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Answer» `331mm "of" HG` |
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